如果有理数a,b满足|ab-2|+(1-b)^2=0
试求1/ab+1/(a+1 )(b+1)+1/(a+2)(b+2)+…1/(a+2009)(b+2009)的值
人气:418 ℃ 时间:2020-04-08 18:02:42
解答
|ab-2|=0(1-b)^2=0 所以b=1,a=21/ab+1/(a+1 )(b+1)+1/(a+2)(b+2)+…1/(a+2009)(b+2009)=1/2+1/(3*2)+1/(4*3)+...+1/(2011*2010)=1/2+(1/2-1/3)+(1/3-1/4)+...+(1/2010-1/2011)=1-1/2011=2010/2011
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