假若a^2+a+a+1=0,求a^2014+a^2012+a^2012+3的值(过程)
人气:388 ℃ 时间:2020-03-20 05:54:30
解答
a^2+2a+1=(a+1)^2=0
a=-1;
(-1)^2014+(-1)^2012+(-1)^2012+3
=1+1+1+3
=6
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