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关于x的不等式 (3x2++2x+2)/(x2+x+1)
人气:269 ℃ 时间:2020-05-20 02:09:42
解答
(3x2++2x+2)/(x2+x+1)
=2+x^2/(x^2+x+1)
=2+1/(1+1/x+1/x^2)
=1+1/[(1/x+1/2)^2+3/4]
≤1+1/(3/4)
=1+4/3
=7/3
m>7/3
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