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lim(a趋于0)∫(a到a+1)dx/(1+x^2+a^2)
人气:323 ℃ 时间:2020-06-03 17:20:56
解答
=lim(a趋于0) (1/(1+a^2))·∫(a到a+1) dx/(1+(x/√(1+a^2))²)=lim(a趋于0) (1/√(1+a^2))·∫(a到a+1) d(x/√(1+a^2)) /(1+(x/√(1+a^2))²)=lim(a趋于0) (1/√(1+a^2))·arctan(x/√(1+a^2)) |(a到a+1) =...
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