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计算1/(1×2×3)+1/(2×3×4)+1/(3×4×5)+…+1/(11×12×13),要过程
人气:136 ℃ 时间:2020-05-11 22:14:48
解答
1/(1×2×3)+1/(2×3×4)+1/(3×4×5)+…+1/(11×12×13)
=1/2×【1/(1×2)-1/(2×3)+1/(2×3)-1/(3×4)+1/(3×4)-1/(4×5)+…+1/(11×12)-1/(12×13)】
=1/2×【1/(1×2)-1/(12×13)】
=1/2×【1/2-1/156】
=1/2×77/156
=77/312
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