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化简1/(b+c)(c/b-b/c)+1/(a+c)(a/c-c/a)+1/(a+b)(b/a-a/b)要有过程谢谢
人气:213 ℃ 时间:2020-04-02 02:45:24
解答
1/(b+c)(c/b-b/c)+1/(a+c)(a/c-c/a)+1/(a+b)(b/a-a/b)=1/(b+c) × (c²-b²)/bc +1/(a+c) × (a²-c²)/ac +1/(a+b) × (b²-a²)/ab=(c-b)/bc + (a-c)/ac + (b-a)/ab=(ac-ab+ab-bc+bc-ac)/...
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