设∠A,∠B,∠C成等差,其对边a,b,c成等比.∵△ABC的三个内角成等差数列∴2∠B=∠A+∠C==>∠B=60又∵b²=ac由余弦定理得b²=a²+c²-2accosBac=a²+c²-ac(a-c)²=0==>a=c==>∠A=∠C=60∴...