设安排 x 名工人做甲种零件,y 名工人做乙种零件,z 名工人做丙种零件.
可列方程组：x+y+z = 86 ,(5x)/3 = (4y)/2 = (3z)/1 .
设 (5x)/3 = (4y)/2 = (3z)/1 = k ,可得：x = (3/5)k ,y = (1/2)k ,z = (1/3)k ；
代入 x+y+z = 86 ,可得：(43/30)k = 86 ,
解得：k = 60 ,
可得：x = (3/5)k = 36 ,y = (1/2)k = 30 ,z = (1/3)k = 20 ；
即：安排 36 名工人做甲种零件,30 名工人做乙种零件,20 名工人做丙种零件.