(1+Sinx+Cosx+SinxCosx)/(Sinx+Sin^2 x)怎么化简成(Cscx+1+Cotx+Cosx)/(1+S_数学解答

(1+Sinx+Cosx+SinxCosx)/(Sinx+Sin^2 x)怎么化简成(Cscx+1+Cotx+Cosx)/(1+Sinx)?

人气：301 ℃　时间：2020-03-22 18:19:37

解答

分子分母同时除以sinx (1+Sinx+Cosx+SinxCosx)/(Sinx+Sin^2 x)= [(1+Sinx+Cosx+SinxCosx)/]/(Sinx+Sin^2 x)sinx=(Cscx+1+Cotx+Cosx)/(1+Sinx)