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数学
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当k为何值时,方程组4x+3y=1,kx+2(k-1)=3的解xy互为相反数
人气:302 ℃ 时间:2019-08-21 10:47:02
解答
由kx+2(k-1)=3得:x=5-2k/k
∵xy互为相反数
∴y=-5-2k/k
把x,y代入4x+3y=1得:
4×(5-2k/k)+3×(-5-2k/k)=1
化简得5-2k/k=1
∴k=5/3
∴x=1,y=-1
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