设函数y=sinx+根号3cosx
当x属于[0,无限大)时求它的振幅,频率和初相.(2)若x属于[0,2派),求单调递减区间
人气：331 ℃ 时间：2020-02-04 00:06:25
解答
y=sinx+根号3cosx
-2sin(x+π/3) ,振幅A=2,频率f=1/2π,初相π/3
[0,2π)
π/2
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