1.已知sin2α=1/4,α属于(π/4,π/2),则 cosα-sinα=?2.已知sinα+cosα=1/3,0<α<π,求
2.求sin2α,cos2α,tan2α
人气:407 ℃ 时间:2019-10-24 03:54:34
解答
1.
(cosα-sinα)^2
=1-2sinαcosα
=1-sin2α
=1-1/4
=3/4
而 α∈(π/4,π/2)时,cosα
推荐
- 已知π/2
- 已知:0<α<π/2<β<π,cos(β-π/4)=1/3,sin(α+β)=4/5 (1)求sin2β (2)求cos(α+π/4)的值
- 已知sinα=2/3,cosβ=-3/4,α∈(π/2,π),β是第三象限的角 (1)求sin2α
- 已知:0<α<π/2<β<π,cos﹙β-π/4﹚=1/3,sin(α+β)=4/5 1,求sin2β的值
- 已知π/2<β<α<3π/4,cos(α-β)=12/13,sin(α+β)=-3/5 求sin2α的值
- 关于whether和whether or not?
- 你说的白是什么白?你说的黑是什么黑?
- they had to wait until somebody told them___later
猜你喜欢