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已知:0<α<π/2<β<π,cos(β-π/4)=1/3,sin(α+β)=4/5 (1)求sin2β (2)求cos(α+π/4)的值
人气:485 ℃ 时间:2019-11-06 11:22:31
解答
cos(β-π/4)=1/3cos2(β-π/4)=2[cos(β-π/4)]^2-1=-7/9cos(2β-π/2)=-7/9cos(π/2-2β)=-7/9sin2β=-7/9cos(β-π/4)=1/3,sin(α+β)=4/5,0<α<π/2<β<πsin(β-π/4)=2√2/3cos(α+β)=-3/5cos(α+π/4)=c...
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