已知Sn是等比数列前n项和,S3、S6、S9成等差数列,求证a2 a5 a8为等差数列.三种解法.证明一因为S3.S9.S6成等差数列 2S9=S3+S6 2a1(1-q^8)/(1-q)=a1(1-q^2)/(1-q)+a1(1-q^5)/(1-q) 2(1-q^8)=2-q^2-q^5 2q^8=q^2+q^5 2q^...