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几道数学题,分解公因式的,
a-1+1/a+1
1/2axy+2/3bx^2-3/4xy^2
1/(4x^2-4y^2)+(3x)/(2x^2-4xy^2+2y^2)
(x+2)/(x-2)—(x^2+2x)/(x^2-4)
搞错,是分式分解,对不起
人气:372 ℃ 时间:2020-06-03 11:17:26
解答
a-1+1/a+1
=[(a-1)(a+1)+1]/(a+1)
=(a^2-1+1)/(a+1)
=a^2/(a+1)
1/2axy+2/3bx^2-3/4xy^2
=(6bxy+8ay^2-9abx)/(12abx^2y^2)
1/(4x^2-4y^2)+(3x)/(2x^2-4xy^2+2y^2)
=1/4(x-y)(x+y)+3x/2(x-y)^2
=[(x-y)+6x(x+y)]/[4(x+y)(x-y)^2]
=(x-y+6x^2+6xy)/[4(x+y)(x-y)^2]
(x+2)/(x-2)—(x^2+2x)/(x^2-4)
=(x^2+4x+4-x^2-2x)/x+2)(x-2)
=(2x+4)/x+2)(x-2)
=2/(x-2)
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