解由x-1/x+1≥2得x-1/x+1-2≥0即x-1/x+1-2（x+1）/(x+1)≥0即[x-1-2（x+1）]/(x+1)≥0即（-x-3）/(x+1)≥0即（x+3）/(x+1)≤0即（x+3）(x+1)≤0且x+1≠0即解得-3≤x＜-1故不等式 x-1/x+1≥2的解集为｛x/-3≤x＜-1｝...