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2/(x+1)≤1解不等式
人气:234 ℃ 时间:2020-02-05 09:57:55
解答
解不等式2/(x+1)≤1
[2/(x+1)]-1=(-x+1)/(x+1)=-(x-1)/(x+1)≤0,即(x-1)(x+1)≧0,
故得x
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