√（8a³b²)·[-3/2√(2a²b)]÷√(9ab)（a＞0,b＞0）
=2ab√(2a)·[-3/2*a√(2b)]÷3√(ab)
=2ab√(2a)·[-3/2*a√(2b)]*1/[3√(ab)]
=-6a²b√(ab)*1/[3√(ab)]
=-2a²b