题目抄错了吧?
|x-1|+(y×2)²+|2-3|=0,|x-1|≥0,(y×2)²≥0,|2-3|≥0
所以|x-1|=(y×2)²=|2-3|=0
即x=1,y=0,z=3
x-y+z
=1-0+3
=4