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化简f(x)=(1-√2*cos(2x-π/4))/sin(π/2-x)
人气:251 ℃ 时间:2020-06-07 09:53:05
解答
先看分子
1-√2*cos(2x-π/4)
=1-√2[cos2xcos(π/4)+sin2xcos(π/4)]
=1-cos2x-sin2x
=2sin²x-2sinxcosx
=2sinx(sinx-cosx)
分母=cosx
原式=2tanx(sinx-cosx)
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