如图所示,在△ABC中,AB=AC,D为BC上一点,且CD=AC,连接AD,且AD=BD,求∠BAC的度数.
人气:180 ℃ 时间:2019-10-23 08:39:12
解答
因为AB=AC
所以∠B=∠C
同理得:∠CAD=∠CDA ∠B=∠BAD
可得:∠B=∠BAD
由于∠CDA=∠B+∠BAD
故∠CAD=∠CDA=2∠BAD
故∠BAC=3∠BAD=3∠B
三角形内角和为180,即:∠BAC+∠B+∠C=180
即:5∠B=180
得∠B=36
故可得:∠BAC=108
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