设f(x+y,xy)=x²+y²+xy,则df(x,y)=
人气：252 ℃ 时间：2020-06-24 04:25:26
解答
f(x+y,xy)=x²+y²+xy
=x²+y²+2xy-xy
=(x+y)²-xy
f(x,y)=x²-y
df(x,y)/dx=2x
df(x,y)=2xdx
df(x,y)/dy=-1
df(x,y)=-dy
所以
df(x,y)==2xdx-dy
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