1/n(n+1)(n+2)=[1/n-1/(n+1)]-[1/(n+1)-1/(n+2)]2/1*2*3+2/2*3*4+2/3*4*5+.2/*8*9*10 =2*(1/1*2*3+1/2*3*4+...+1/8*9*10)=2*[(1-1/2+1/2-1/3+...+1/8-1/9)-(1/2-1/3+1/3-1/4+...+1/9-1/10)]=2*[(1-1/9)-(1/2-1/10)]=...