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x^2+y^2-2x+6y+10=0,求(x-y)^2-(x^2-y^2)
人气:168 ℃ 时间:2020-06-27 11:16:50
解答
x^2+y^2-2x+6y+10
=(x-1)^2+(y+3)^2=0
x=1,y=-3
(x-y)^2-(x^2-y^2)
=(x-y)^2-(x+y)(x-y)
=(x-y)(x-y-x-y)
=(x-y)*(-2y)
=(1-(-3))*(-2*(-3))
=4*6
=24
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