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数列 (16 0:36:31)
设数列f(x)=1/2^x+根号2,求f(-5)+f(-4)+...+f(0)+...+f(6)的值
人气:463 ℃ 时间:2020-01-29 22:42:09
解答
求 f(x) + f(1-x) f(x) = 1/(2^x + √2)f(1-x) = 1/[2^(1-x) + √2) .(分子、分母同时乘以 2^x )= 2^x/(2 + √2 * 2^x) .(分母中提取出 √2)= (2^x/√2) * (1/√2 + 2^x) = (2^x/√2) * f(x)f(x) + f(1-x)= (1+ ...
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