log2(x+14)-log2(x+6)=3-log2(x+2)
∴log2[(x+14)/(x+6)]=log2[8/(x+2)]
∴(x+14)/(x+6)=8/(x+2)且(x+14)/(x+6)>0,8/(x+2)>0
∴两边同乘以(x+6)(x+2)得 x^2+16x+28=8x+48
化简得 x^2+8x-20=0
∴x=2或x=-10,
带回8/(x+2),发现当x=-10时,8/(x+2)