log2^(4^x+4)=x+log2^[2^(x+1)-3]log2^(4^x+4)-log2^[2^(x+1)-3]=xlog2[(4^x+4)/(2^(x+1)-3)]=x(4^x+4)/(2^(x+1)-3)=2^x4^x+4=2^x[2^(x+1)-3]4^x+4=2*4^x-3*2^x-4^x+3*2^x+4=0设 2^x=t t>0则-t²+3t+4=0t²...