An object with an initial velocity of 4m/s moves along a straight axis uder constant acceleration.Three seconds later ,its velocity is 14m/s.How far did it travel during this time?
人气：394 ℃ 时间：2020-03-28 08:21:13
解答
一个物体以初始4m/s速度沿直线恒定加速度运动,3秒后速度为14m/s,求运动距离?
V0+at=V1
4+3a=14
得：a=10/3
S=V0t+0.5at^2
=4*3+0.5*（10/3）*3^2
=27
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