配凑:f(x-2)=4(x-2)方+11x-9=4(x-2)方+11(x-2)+13f(x)=4x方+11x+13换元:x-2=tx=t+2代入原式,f(t)=4(t+2)方-5(t+2)+7即解待定系数:设f(x)=ax方+bx+c则a(x-2)方+b(x-2)+c=4x方-5x+7系数对应相等,即解...