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y=根号6cosx-根号2sinx的值域
人气:237 ℃ 时间:2020-01-31 12:44:50
解答
y=√6cosx-√2sinx
=√2(√3cosx-sinx)
=2√2(√3/2*cosx-1/2*sinx)
=2√2(cosπ/6*cosx-sinπ/6*sinx)
=2√2cos(π/6+x)
-1<=cos(π/6+x)<=1
-2√2<=2√2cos(π/6+x)<=2√2
y∈[-2√2,2√2]
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