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求y=(4x∧2-1)÷(x∧2-1)的n阶导数
人气:487 ℃ 时间:2020-05-22 05:28:39
解答
y=(4x²-1)÷(x²-1)=4+[3/(x²-1)]=4+(3/2)*[1/(x-1)]-(3/2)*[1/(x+1)];y'=-(3/2)/(x-1)²+(3/2)/(x+1)²;y"=(3/2)(1*2)/(x-1)³-(3/2)(1*2)/(x+1)³;……y'(n)=(-1)^n(3/2)*n!/(x-...
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