已知：ab互为相反数,
a+b=0;
c,d互为倒数,
cd=1;
x＝3(a－1)-(a-2b),
=3a-3-a+2b
=2a+2b-3
=-3;
y=cd²+d²－(d²＋d－2),
=cd²+d²-d²-d+2
=d+d²-d²-d+2
=2;
求3分之2x－y－6分之3x＋2y的值.
=(4x-2y-3x-2y)/6
=(x-4y)/6
=(-3-4×2)/6
=-11/6;
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