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急求等差数列通项公式和前n项和公式的证明方法~
人气:409 ℃ 时间:2020-04-26 19:39:30
解答
设数列{an}是等差数列,其公差为d,d≠0,根据等差数列的定义:an - a(n-1) = d∴a2- a1= da3 - a2 = da4 - a3 = d.an - a(n-1) = d上述各式相加:an - a1 = (n-1)d即:an = a1 + (n-1)d令Sn = a1 + a2 +.+ an根据an = ...
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