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数学
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(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
SORRY打错了
(3x^2+9x+7)/(x-1)-(2x^2+4x-3)/(x+1)-(x^3+x+1)/(x^2-1)=
人气:488 ℃ 时间:2020-02-03 16:19:43
解答
=(3x^2+9x+7)(x+1)/(x^2-1)-(2x^2+4x-3)(x-1)/(x^2-1)-(x^3+x+1)/(x^2-1)
=(3x^3+12x^2+16x+7)/(x^2-1)-(2x^3+2x^2-7x+3)/(x^2-1)-(x^3+x+1)/(x^2-1)
=(10x^2+22x+3)/(x^2-1)
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巧算(3x^2+9x+7)/(x+1)-(2x^2-4x-3)/(x-1)-(x^2+x+1)/(x^2-1)
(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=
解方程(3x^2+9x+7)/(x+1)-(2x^2+4x-3)/(x-1)-(x^3+x+1)/(x^2-1)=0
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