1、设z=3i+b,则9+b^2=(1-b)^2 => b=-4
z=3i-4
2、(1+i)^2*(3+4i)^2/[2(3i-4)]
=2i*(3+4i)^2/[2(3i-4)]
=-(3+4i)^2/(-3-4i) 分子分母同乘以i
=(3+4i)^2/(3+4i)
=3+4i