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lim(x→0){[sinx-sin(sinx)]sinx}/x^4
人气:115 ℃ 时间:2020-07-07 06:54:36
解答
lim(x→0){[sinx-sin(sinx)]sinx}/x^4=lim(x→0){[sinx-sin(sinx)]x}/x^4=lim(x→0)[sinx-sin(sinx)]/x³=lim(x→0){[cosx-cos(sinx)cosx]/3x²=lim(x→0){[-sinx+sin(sinx)cos²x+...
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