求定积分(上限2,下限1)(1/x+1/x^2)dx
没钱了.不管怎么样都错了
人气:188 ℃ 时间:2019-11-06 23:33:12
解答
(1/x+1/x^2)dx
=(lnX-1/X)(从1到2)
=(ln2-1/2)-(ln1-1/1)
=ln2+1/2
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