| k2 |
| x |
设两个函数的图象交点为P(x,y),|x|=4,|y|=3.
当x=4,y=3时,
代入y=k1x,有3=4k1,解得k1=
| 3 |
| 4 |
∴y=
| 3 |
| 4 |
代入y=
| k2 |
| x |
| k2 |
| 4 |
∴y=
| 12 |
| x |
当x=-4,y=-3时结果同上;
当x=4,y=-3时代入y=k1x,有-3=4k1,解得k1=-
| 3 |
| 4 |
∴y=−
| 3 |
| 4 |
代入y=
| k2 |
| x |
| k2 |
| 4 |
∴y=−
| 12 |
| x |
当x=-4,y=3时结果同上.
∴所求函数的解析式为:y=
| 3 |
| 4 |
| 12 |
| x |
| 3 |
| 4 |
| 12 |
| x |
| k2 |
| x |
| 3 |
| 4 |
| 3 |
| 4 |
| k2 |
| x |
| k2 |
| 4 |
| 12 |
| x |
| 3 |
| 4 |
| 3 |
| 4 |
| k2 |
| x |
| k2 |
| 4 |
| 12 |
| x |
| 3 |
| 4 |
| 12 |
| x |
| 3 |
| 4 |
| 12 |
| x |