1
mH2SO4=47*1.07=50.29g
nH2=0.2/2=0.1mol
Mg+H2SO4=MgSO4+H2
1 1 1 1
X Y 0.1
X=0.1mol
mMg=0.1*24=2.4g
MgO=3.2-2.4=0.8g
Y=0.1mol
mMgSO4=120*0.1=12g
mH2=0.1*2=0.2g
m溶液=3.2+50.29-0.2=53.29g
%=12/53.29=22.5%
3
22gNaOH 100gH2O 饱和
mNaOH/mH2O=22/100=11/50
设mNaOh=11X 余H2O=50x
2Na+2H2O=2NaOH+H2
46___36___80___2
Y_100-50X_11X
解得X=8000/4396
Y=50600/4396 g