(0)由sin²α＋cos²α=1得sinα=3/5cos(α-π/6)=cosα·cos(π/6)＋sinα·sin(π/6)=-4/5·√3/2＋3/5·1/2=(3-4√3)/10(1)最大值为1说明A=1过点M,代入解析式,得sin(wπ/3＋φ)=1/2下面就做不下去了,因为...