(1)先化简f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a=sinxcosπ/6+sinπ/6cosx+sinxcosπ/6-sinπ/6cosx+cosx+a=√3倍sinx+cosx+a=2sin(x+π/6)+a当sin(x+π/6)=1时,f(x)最大,最大值为2+a∴2+a=1 ∴a=-1(2)由（1）可得f(x...