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lim[(1-cosX)/x的平方]是多少,X趋近于0时
人气:376 ℃ 时间:2020-04-01 18:38:20
解答
1- cosX = 1 - [ 1 - 2(sinx/2)^2] = 2[sin(x/2)]^2
1-cosX/X^2 = 2[sin(x/2)]^2/x^2
= (1/2)* [sin(x/2)/(x/2)]^2
sin(x/2)/(x/2) 当x趋近于0时,其极限为1
(这是书上的基本定理)
因此
lim[(1-cosX)/x^2] = 1/2
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