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已知α为第四象限角,化简:cosα√[(1-sinα)/(1+sinα)]+sinα√[(1-cosα)/(1+cosα)]
人气:471 ℃ 时间:2020-03-30 21:31:30
解答
(1-sinα)/(1+sinα)=(1-sinα)²/(1-sinα)(1+sinα)=(1-sinα)²/(1-sin²α)=(1-sinα)²/cos²α(1-cosα)/(1+cosα)=(1-cosα)²/(1+cosα)(1-cosα)=(1-cosα)²/(1-cos²α)...
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