已知x+y=1/2,求x^2y+xy^2的值 少一个条件已知x=6,y=1/6,求x^2+xy-5x-5y的值原式=x(x+y)-5(x+y)=(x+y)(x-5)=(6+1/6)(6-5)=37/61.825^2x3-175^2x3=3(825²-175²)=3(825+175)(825-175)=3×1000×650=19500002....已知x+y=1/2，xy1/8,求x^2y+xy^2的值你还是少一个等于号，不过我看懂了x^2y+xy^2=xy(x+y)=1/8×1/2=1/16