原式=
−(b+c)•a |
bc |
−(a+c)•b |
ac |
−(a+b)•c |
ab |
=-(
ba+ca |
bc |
ab+cb |
ac |
ac+bc |
ab |
=−(
a |
b |
a |
c |
b |
a |
b |
c |
c |
a |
c |
b |
=
−(b+c) |
a |
−(a+c) |
b |
−(a+b) |
c |
=
a |
a |
b |
b |
c |
c |
故选A.
a2 |
bc |
b2 |
ca |
c2 |
ab |
−(b+c)•a |
bc |
−(a+c)•b |
ac |
−(a+b)•c |
ab |
ba+ca |
bc |
ab+cb |
ac |
ac+bc |
ab |
a |
b |
a |
c |
b |
a |
b |
c |
c |
a |
c |
b |
−(b+c) |
a |
−(a+c) |
b |
−(a+b) |
c |
a |
a |
b |
b |
c |
c |