已知:如图,在等腰三角形ABC中,AB=AC,BD垂直于AC,CE垂直于AB,垂足分别为点D,E,求
求证:BE=CD
人气:198 ℃ 时间:2019-08-16 02:05:33
解答
证明:
∵BD⊥AC,CE⊥AB
∴∠ADB=∠AEC=90
∵AB=AC,∠BAD=∠CAE
∴△ABD≌△ACE (AAS)
∴AD=AE
∵BE=AB-AE,CD=AC-AD
∴BE=CD
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