> 数学 >
lim(2^x/1次幂-1)/(2^x/1次幂+1)
人气:471 ℃ 时间:2020-04-12 18:12:03
解答
lim(x→0)[(2^x-1)/(2^x+1)]
=lim(x→0)(2^x-1)/[lim(x→0)(2^x+1)]
=(2^0-1)/(2^0+1)
=(1-1)/(1+1)
=0
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版