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1)有一道题“先化简再求值:{x
2)若x>1,m=x-1/x,n=x/x+1,试比较m,n的大小关系 (3)分解因式:a^5-1/2a^3b^2+1/16ab^4 (4)若(4a-1)/(a+2)(a-10=m/(a+2)+n/(a-1),求m,n的值
人气:476 ℃ 时间:2020-02-26 05:33:45
解答
2)m-n=(x-1)/x-x/(x+1)=(x^2-1-x^2)/[x(x+1)]=-1/[x(x+1)]
∵x>1
∴x(x+1)>0
m-n<0
m3) a^5-1/2a^3b^2+1/16ab^4=a(a^4-1/2a^2b^2+1/16b^2)=a(a-1/4b)^2
4) (4a-1)/[(a+2)(a-10)]
=m/(a+2)+n/(a-1)
=[m(a-1)+n(a+2)]/[(a+2)(a-10)]
=[(m+n)a-m+2n]/[(a+2)(a-10)]
m+n=4,-m+2n=-1
m=3,n=1
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