f(x)=(sinx)^2/2*(1/tan(x/2)-tan(x/2))+√3/2cos2x
=(sinx)^2[(cos(x/2))^2-(sin(x/2))^2]/[2sin(x/2)cos(x/2)]+√3/2cos2x
=(sinx)^2cosx/sinx+√3/2cos2x
=(1/2)(sin2x)+(√3/2)cos2x
=sin(2x+π/3)
π/2f(x)=(sinx)^2/2*(1/tan(x/2)-tan(x/2))+√3/2cos2x=(sinx)^2[(cos(x/2))^2-(sin(x/2))^2]/[2sin(x/2)cos(x/2)]+√3/2cos2x我不太懂 能分开解释一下么？