设limf(x) (x→1)=A
则limf(x) (x→1)=lim(3x²＋2xlimf(x))(x→1)
A=3+2A
解得A=-3
所以f(x)=3x²＋2xlimf(x) (x→1)
=3x²＋2Ax
=3x²-6x
答案不对的话告诉我,看看哪里错了